Edit

Share via


TreeViewHitTestInfo.Node Property

Definition

Gets the TreeNode at the position indicated by a hit test of a TreeView control.

public:
 property System::Windows::Forms::TreeNode ^ Node { System::Windows::Forms::TreeNode ^ get(); };
public System.Windows.Forms.TreeNode Node { get; }
public System.Windows.Forms.TreeNode? Node { get; }
member this.Node : System.Windows.Forms.TreeNode
Public ReadOnly Property Node As TreeNode

Property Value

The TreeNode at the position indicated by a hit test of a TreeView control.

Examples

The following code example demonstrates how to use the Node property. To run this example, create a Windows Form that contains a TreeView named treeView1, and populate it with several levels of nodes. Paste the following code into a form, and associate the MouseDown event of treeView1 with the treeView1_MouseDown method.

private:
    void InitialTreeView_MouseDown(Object^ sender, MouseEventArgs^ e)
    {
        TreeViewHitTestInfo^ info = initialTreeView->HitTest(e->X, e->Y);
        TreeNode^ hitNode;

        if (info->Node != nullptr)
        {
            hitNode = info->Node;
            MessageBox::Show(hitNode->Level.ToString());
        }
    }
void treeView1_MouseDown(object sender, MouseEventArgs e)
{
    TreeViewHitTestInfo info = treeView1.HitTest(e.X, e.Y);
    TreeNode hitNode;
    if (info.Node != null) {
        hitNode = info.Node;
        MessageBox.Show(hitNode.Level.ToString());
    }
}
Sub treeView1_MouseDown(ByVal sender As Object, ByVal e As MouseEventArgs) 
    Dim info As TreeViewHitTestInfo = treeView1.HitTest(e.X, e.Y)
    Dim hitNode As TreeNode
    If (info.Node IsNot Nothing) Then
        hitNode = info.Node
        MessageBox.Show(hitNode.Level.ToString())
    End If

End Sub

Remarks

If the hit test location is not on a TreeNode, the Node property will be null.

Applies to