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Produces the set union of two sequences.
Union<TSource>(IQueryable<TSource>, IEnumerable<TSource>) |
Produces the set union of two sequences by using the default equality comparer. |
Union<TSource>(IQueryable<TSource>, IEnumerable<TSource>, IEqualityComparer<TSource>) |
Produces the set union of two sequences by using a specified IEqualityComparer<T>. |
Produces the set union of two sequences by using the default equality comparer.
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static System::Linq::IQueryable<TSource> ^ Union(System::Linq::IQueryable<TSource> ^ source1, System::Collections::Generic::IEnumerable<TSource> ^ source2);
public static System.Linq.IQueryable<TSource> Union<TSource>(this System.Linq.IQueryable<TSource> source1, System.Collections.Generic.IEnumerable<TSource> source2);
static member Union : System.Linq.IQueryable<'Source> * seq<'Source> -> System.Linq.IQueryable<'Source>
<Extension()>
Public Function Union(Of TSource) (source1 As IQueryable(Of TSource), source2 As IEnumerable(Of TSource)) As IQueryable(Of TSource)
The type of the elements of the input sequences.
A sequence whose distinct elements form the first set for the union operation.
A sequence whose distinct elements form the second set for the union operation.
An IQueryable<T> that contains the elements from both input sequences, excluding duplicates.
source1
or source2
is null
.
The following code example demonstrates how to use Union<TSource>(IQueryable<TSource>, IEnumerable<TSource>) to obtain the set union of two sequences.
int[] ints1 = { 5, 3, 9, 7, 5, 9, 3, 7 };
int[] ints2 = { 8, 3, 6, 4, 4, 9, 1, 0 };
// Get the set union of the items in the two arrays.
IEnumerable<int> union = ints1.AsQueryable().Union(ints2);
foreach (int num in union)
Console.Write("{0} ", num);
/*
This code produces the following output:
5 3 9 7 8 6 4 1 0
*/
Dim ints1() As Integer = {5, 3, 9, 7, 5, 9, 3, 7}
Dim ints2() As Integer = {8, 3, 6, 4, 4, 9, 1, 0}
' Get the set union of the items in the two arrays.
Dim union = ints1.AsQueryable().Union(ints2)
Dim output As New System.Text.StringBuilder
For Each num As Integer In union
output.Append(String.Format("{0} ", num))
Next
' Display the output.
MsgBox(output.ToString())
' This code produces the following output:
' 5 3 9 7 8 6 4 1 0
The Union<TSource>(IQueryable<TSource>, IEnumerable<TSource>) method generates a MethodCallExpression that represents calling Union<TSource>(IQueryable<TSource>, IEnumerable<TSource>) itself as a constructed generic method. It then passes the MethodCallExpression to the CreateQuery<TElement>(Expression) method of the IQueryProvider represented by the Provider property of the source1
parameter.
The query behavior that occurs as a result of executing an expression tree that represents calling Union<TSource>(IQueryable<TSource>, IEnumerable<TSource>) depends on the implementation of the type of the source1
parameter. The expected behavior is that the set union of the elements in source1
and source2
is returned.
Product | Versions |
---|---|
.NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9, 10 |
.NET Framework | 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
.NET Standard | 2.0, 2.1 |
UWP | 10.0 |
Produces the set union of two sequences by using a specified IEqualityComparer<T>.
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static System::Linq::IQueryable<TSource> ^ Union(System::Linq::IQueryable<TSource> ^ source1, System::Collections::Generic::IEnumerable<TSource> ^ source2, System::Collections::Generic::IEqualityComparer<TSource> ^ comparer);
public static System.Linq.IQueryable<TSource> Union<TSource>(this System.Linq.IQueryable<TSource> source1, System.Collections.Generic.IEnumerable<TSource> source2, System.Collections.Generic.IEqualityComparer<TSource> comparer);
public static System.Linq.IQueryable<TSource> Union<TSource>(this System.Linq.IQueryable<TSource> source1, System.Collections.Generic.IEnumerable<TSource> source2, System.Collections.Generic.IEqualityComparer<TSource>? comparer);
static member Union : System.Linq.IQueryable<'Source> * seq<'Source> * System.Collections.Generic.IEqualityComparer<'Source> -> System.Linq.IQueryable<'Source>
<Extension()>
Public Function Union(Of TSource) (source1 As IQueryable(Of TSource), source2 As IEnumerable(Of TSource), comparer As IEqualityComparer(Of TSource)) As IQueryable(Of TSource)
The type of the elements of the input sequences.
A sequence whose distinct elements form the first set for the union operation.
A sequence whose distinct elements form the second set for the union operation.
An IEqualityComparer<T> to compare values.
An IQueryable<T> that contains the elements from both input sequences, excluding duplicates.
source1
or source2
is null
.
The Union<TSource>(IQueryable<TSource>, IEnumerable<TSource>, IEqualityComparer<TSource>) method generates a MethodCallExpression that represents calling Union<TSource>(IQueryable<TSource>, IEnumerable<TSource>, IEqualityComparer<TSource>) itself as a constructed generic method. It then passes the MethodCallExpression to the CreateQuery<TElement>(Expression) method of the IQueryProvider represented by the Provider property of the source1
parameter.
The query behavior that occurs as a result of executing an expression tree that represents calling Union<TSource>(IQueryable<TSource>, IEnumerable<TSource>, IEqualityComparer<TSource>) depends on the implementation of the type of the source1
parameter. The expected behavior is that the set union of the elements in source1
and source2
is returned. The comparer
parameter is used to compare values.
Product | Versions |
---|---|
.NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9, 10 |
.NET Framework | 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
.NET Standard | 2.0, 2.1 |
UWP | 10.0 |
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