Queryable.AsQueryable Method

Source:

Queryable.cs

Source:

Queryable.cs

Source:

Queryable.cs

Source:

Queryable.cs

public:
[System::Runtime::CompilerServices::Extension]
 static System::Linq::IQueryable ^ AsQueryable(System::Collections::IEnumerable ^ source);

public static System.Linq.IQueryable AsQueryable(this System.Collections.IEnumerable source);

static member AsQueryable : System.Collections.IEnumerable -> System.Linq.IQueryable

<Extension()>
Public Function AsQueryable (source As IEnumerable) As IQueryable

Parameters

Returns

An IQueryable that represents the input sequence.

Exceptions

Remarks

If the type of source implements IQueryable<T>, AsQueryable(IEnumerable) returns it directly. Otherwise, it returns an IQueryable<T> that executes queries by calling the equivalent query operator methods in Enumerable instead of those in Queryable.

This method assumes that source implements IEnumerable<T> for some T. At runtime, the result is of type IQueryable<T> for the same T. This method is useful in dynamic scenarios when you do not statically know the type of T.

Source:

Queryable.cs

Source:

Queryable.cs

Source:

Queryable.cs

Source:

Queryable.cs

public:
generic <typename TElement>
[System::Runtime::CompilerServices::Extension]
 static System::Linq::IQueryable<TElement> ^ AsQueryable(System::Collections::Generic::IEnumerable<TElement> ^ source);

public static System.Linq.IQueryable<TElement> AsQueryable<TElement>(this System.Collections.Generic.IEnumerable<TElement> source);

static member AsQueryable : seq<'Element> -> System.Linq.IQueryable<'Element>

<Extension()>
Public Function AsQueryable(Of TElement) (source As IEnumerable(Of TElement)) As IQueryable(Of TElement)

Type Parameters

Parameters

Returns

An IQueryable<T> that represents the input sequence.

Exceptions

Examples

The following code example demonstrates how to use AsQueryable<TElement>(IEnumerable<TElement>) to convert an IEnumerable<T> to an IQueryable<T>.

List<int> grades = new List<int> { 78, 92, 100, 37, 81 };

// Convert the List to an IQueryable<int>.
IQueryable<int> iqueryable = grades.AsQueryable();

// Get the Expression property of the IQueryable object.
System.Linq.Expressions.Expression expressionTree =
    iqueryable.Expression;

Console.WriteLine("The NodeType of the expression tree is: "
    + expressionTree.NodeType.ToString());
Console.WriteLine("The Type of the expression tree is: "
    + expressionTree.Type.Name);

/*
    This code produces the following output:

    The NodeType of the expression tree is: Constant
    The Type of the expression tree is: EnumerableQuery`1
*/

Dim grades As New List(Of Integer)(New Integer() {78, 92, 100, 37, 81})

' Convert the List to an IQueryable<int>.
Dim iqueryable As IQueryable(Of Integer) = grades.AsQueryable()

' Get the Expression property of the IQueryable object.
Dim expressionTree As System.Linq.Expressions.Expression = _
    iqueryable.Expression

MsgBox("The NodeType of the expression tree is: " _
    & expressionTree.NodeType.ToString())
MsgBox("The Type of the expression tree is: " _
    & expressionTree.Type.Name)

' This code produces the following output:
'
' The NodeType of the expression tree is: Constant
' The Type of the expression tree is: EnumerableQuery`1

Remarks

If the type of source implements IQueryable<T>, AsQueryable<TElement>(IEnumerable<TElement>) returns it directly. Otherwise, it returns an IQueryable<T> that executes queries by calling the equivalent query operator methods in Enumerable instead of those in Queryable.