.NET Framework Class Library
Vector3D..::.Divide Method

Updated: November 2007

Divides the specified Vector3D structure by the specified scalar and returns the result as a Vector3D.

Namespace:  System.Windows.Media.Media3D
Assembly:  PresentationCore (in PresentationCore.dll)

Visual Basic (Declaration)
Public Shared Function Divide ( _
    vector As Vector3D, _
    scalar As Double _
) As Vector3D
Visual Basic (Usage)
Dim vector As Vector3D
Dim scalar As Double
Dim returnValue As Vector3D

returnValue = Vector3D.Divide(vector, _
    scalar)
C#
public static Vector3D Divide(
    Vector3D vector,
    double scalar
)
Visual C++
public:
static Vector3D Divide(
    Vector3D vector, 
    double scalar
)
J#
public static Vector3D Divide(
    Vector3D vector,
    double scalar
)
JScript
public static function Divide(
    vector : Vector3D, 
    scalar : double
) : Vector3D
XAML
You cannot use methods in XAML.

Parameters

vector
Type: System.Windows.Media.Media3D..::.Vector3D

The Vector3D structure to be divided.

scalar
Type: System..::.Double

The scalar to divide vector by.

Return Value

Type: System.Windows.Media.Media3D..::.Vector3D

Returns the result of dividing vector by scalar.

The following example shows how to divide a Vector3D structure by a scalar.

C#
                        // Divides a Vector3D by a Scalar using the overloaded / operator.  
                        // Returns a Vector3D.

                        Vector3D vector1 = new Vector3D(20, 30, 40);
                        Vector3D vectorResult = new Vector3D();
                        Double scalar1 = 75;

                        vectorResult = vector1 / scalar1;
                        // vectorResult is approximately equal to (0.26667, 0.4, 0.53333)

Windows Vista

The .NET Framework and .NET Compact Framework do not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.

.NET Framework

Supported in: 3.5, 3.0
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